TeenHelp
Get Advice Quick Ask Support Forums Today's Posts Chat Room

Get Advice Connect with TeenHelp Resources
HelpLINK Chat and Live Help Facebook     Twitter     Tumblr     Instagram    Safety Zone
   Hotlines
   Alternatives
   Calendar


You are not registered or have not logged in
Hello guest! (Not a guest? Log in above!) As a guest you can submit help requests, create and reply to Forum posts, join our Chat Room and read our range of articles & resources. By registering you will be able to get fully involved in our community and enjoy features such as connect with members worldwide, add friends & send messages, express yourself through a Blog, find others with similar interests in Social Groups, post pictures and links, set up a profile and more! Signing up is free, anonymous and will only take a few moments, so click here to register now!



Homework Help If you're stuck with school work, ask in this forum for help from others.

Closed Thread
 
Thread Tools Search this Thread Rate Thread
  (#1 (permalink)) Old
Christinaa317o8 Offline
Christina
Regular TeenHelper
*****
 
Christinaa317o8's Avatar
 
Name: Christina
Age: 30
Gender: Female
Location: New York

Posts: 352
Points: 12,656, Level: 16
Points: 12,656, Level: 16 Points: 12,656, Level: 16 Points: 12,656, Level: 16
Blog Entries: 1
Join Date: January 29th 2009

Red face Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:06 PM

I don't know if anyone posts this stuff, but I really suckkk at Geometry, so if anyone happens to be wicked good, can you let me know if you wanna help?

;]
  (#2 (permalink)) Old
Hyper Sonic Offline
Banned
I can't get enough
*********
 
Hyper Sonic's Avatar
 
Gender: Male
Location: England

Posts: 2,022
Points: 25,325, Level: 23
Points: 25,325, Level: 23 Points: 25,325, Level: 23 Points: 25,325, Level: 23
Blog Entries: 23
Join Date: January 5th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:08 PM

I know some geometry, post the question up and any working you've done and I'll have go
  (#3 (permalink)) Old
BrittneyNicole Offline
live with intention.
I've been here a while
********
 
BrittneyNicole's Avatar
 
Name: Brittney
Age: 33
Gender: Female
Location: Maryland

Posts: 1,783
Points: 21,441, Level: 21
Points: 21,441, Level: 21 Points: 21,441, Level: 21 Points: 21,441, Level: 21
Join Date: January 5th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:15 PM

I'm pretty decent at Geometry. What did you need help with?


"You've just been B-Wildered." -Brian Wilson <3
Trumpet love; Tenderlips.

"Where there is love there is life."- Mahatma Gandhi

"For I know the plans I have for you," declares the Lord, "plans to prosper you and not to harm you, plans to give you hope and a future." - Jeremiah 29:11

  (#4 (permalink)) Old
Christinaa317o8 Offline
Christina
Regular TeenHelper
*****
 
Christinaa317o8's Avatar
 
Name: Christina
Age: 30
Gender: Female
Location: New York

Posts: 352
Points: 12,656, Level: 16
Points: 12,656, Level: 16 Points: 12,656, Level: 16 Points: 12,656, Level: 16
Blog Entries: 1
Join Date: January 29th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:32 PM

So here's my questions.
We're working on ratios which was from 9th grade algerabra but i don't understand it.
Pretty pathetic my teacher tells me.

Okay so heres the problem:

A line segment is divided into two segments, that are in the ratio 3:5. The measure of one segment is 12 centemeters longer than the measure of the other. Find the measure of each segment.


---So I drew a picture of a line. with a point dividing it into two. named one 3x and the other 5x. Thats all I have and its probably wrong. :]

Heres another question

Can the measures of a triangle be in the ratio 5:6:7? Why or Why not?
  (#5 (permalink)) Old
Hyper Sonic Offline
Banned
I can't get enough
*********
 
Hyper Sonic's Avatar
 
Gender: Male
Location: England

Posts: 2,022
Points: 25,325, Level: 23
Points: 25,325, Level: 23 Points: 25,325, Level: 23 Points: 25,325, Level: 23
Blog Entries: 23
Join Date: January 5th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:38 PM

Quote:
Originally Posted by Christinaa317o8 View Post
So here's my questions.
We're working on ratios which was from 9th grade algerabra but i don't understand it.
Pretty pathetic my teacher tells me.

Okay so heres the problem:

A line segment is divided into two segments, that are in the ratio 3:5. The measure of one segment is 12 centemeters longer than the measure of the other. Find the measure of each segment.


---So I drew a picture of a line. with a point dividing it into two. named one 3x and the other 5x. Thats all I have and its probably wrong. :]
I'd have done the same thing. You also know that
Code:
5x = 3x + 12
which solves to give x = 6. Putting that back in we get 3x6cm = 18cm and 5x6cm = 30cm. As 30cm is 12cm bigger than 18cm the answer of 6cm is correct


Quote:
Heres another question

Can the measures of a triangle be in the ratio 5:6:7? Why or Why not?
By measures do you mean angles or lines?

I don't see why angles cannot. Since the sum of the angles in a triangle is 180 you can do
Code:
180/(5+6+7) = 10
so you could have 50, 60 and 70 degrees.

With sides I do not think so because if I construct a triangle with sides a=7x, b=6x and c=5x then by using the cos rule
Code:
cos(C) = (a²+b²-c²)/(2ab)
would give an angle of 0 degrees which evidently cannot be
  (#6 (permalink)) Old
Double X Offline
bee boop
I've been here a while
********
 
Double X's Avatar
 
Name: Kyle
Age: 31
Gender: Male
Location: Boston

Posts: 1,588
Points: 16,164, Level: 18
Points: 16,164, Level: 18 Points: 16,164, Level: 18 Points: 16,164, Level: 18
Blog Entries: 5
Join Date: March 11th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:47 PM

I know you don't need anything from me, but what all of what Hypersonic did all looks right. Except I think that sides of a triangle 5,6,7 could work.

cheers

Last edited by Double X; March 26th 2009 at 09:58 PM.
  (#7 (permalink)) Old
Lozzaa Offline
Member
Experienced TeenHelper
******
 
Lozzaa's Avatar
 
Age: 34
Gender: Female

Posts: 557
Points: 13,431, Level: 16
Points: 13,431, Level: 16 Points: 13,431, Level: 16 Points: 13,431, Level: 16
Join Date: January 6th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 09:55 PM

For the last question : Try pythagorus or trig
  (#8 (permalink)) Old
Christinaa317o8 Offline
Christina
Regular TeenHelper
*****
 
Christinaa317o8's Avatar
 
Name: Christina
Age: 30
Gender: Female
Location: New York

Posts: 352
Points: 12,656, Level: 16
Points: 12,656, Level: 16 Points: 12,656, Level: 16 Points: 12,656, Level: 16
Blog Entries: 1
Join Date: January 29th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 10:02 PM

thankks so muchhh
:]

the second question was suppossed to say measures of the sides**



How do you do these?

The line segments ABC and PQR are divided proportionally by B and Q. AB<BC and PQ<QR.

12. Find PQ when AB = 15, BC = 25, and QR=35.

----I think I might know how to set it up but the wording kind of confuses me.
  (#9 (permalink)) Old
Hyper Sonic Offline
Banned
I can't get enough
*********
 
Hyper Sonic's Avatar
 
Gender: Male
Location: England

Posts: 2,022
Points: 25,325, Level: 23
Points: 25,325, Level: 23 Points: 25,325, Level: 23 Points: 25,325, Level: 23
Blog Entries: 23
Join Date: January 5th 2009

Re: Somebody Wanna Help Me With My Homework?? - March 26th 2009, 10:11 PM

I think it would be the ratio of them since they are proportional: mathematically (note I've took the reciprocal of QR/PQ and BC/AB to take out a step) :

Code:
PQ/QR = AB/BC
so that
Code:
PQ = QR*(AB/AC) = 35*(15/25) = 21
Closed Thread

Bookmarks

Tags
homework, wanna

Thread Tools Search this Thread
Search this Thread:

Advanced Search
Rate This Thread
Rate This Thread:

Posting Rules
You may post new threads
You may post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off


 
User Infomation
Your Avatar

Latest Articles & News
- by Rob
- by Rob

Advertisement



All material copyright ©1998-2024, TeenHelp.
Terms | Legal | Privacy | Conduct | Complaints | Mobile

Powered by vBulletin®.
Copyright ©2000-2024, Jelsoft Enterprises Ltd.
Search engine optimization by vBSEO.
Theme developed in association with vBStyles.